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A number consists of two digits and the digit in the ten’s place exceeds that in the unit’s place by 5. If 5 times the sum of the digits be subtracted from the number, the digits of the number are reversed. Then the sum of digits of the number is
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- 11
- 7
- 9
- 13
Correct Option: C
Let unit’s digit be x.
Ten’s digit = x + 5
Number = 10 (x + 5) + x
= 11x + 50
Again,
11x + 50 – 5 (2x + 5)
= 10x + x + 5
⇒ 11x + 50 – 10x – 25 = 11x + 5
⇒ 10x = 20 ⇒ x = 2
∴ Required sum
= 2x + 5 = 2 × 2 + 5 = 9
