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If the digits in the unit and the ten’s places of a three digit number are interchanged, a new number is formed, which is greater than the original number by 63. Suppose the digit in the unit place of the original number be x. Then, all the possible values of x are
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- 7, 8, 9
- 2, 7, 9
- 0, 1, 2
- 1, 2, 8
Correct Option: B
Let the two digit number be
10y + x where x > y
∴ 10x + y – 10y – x = 63
⇒ 9x – 9y = 63
⇒ x – y = 7
∴ x = 7, 8, 9 and y = 0, 1, 2
