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  1. If a certain number of two digits is divided by the sum of its digits, the quotient is 6 and the remainder is 3. If the digits are reversed and the resulting number is divided by the sum of the digits, the quotient is 4 and the remainder is 9. The sum of the digits of the number is
    1. 6
    2. 9
    3. 12
    4. 4
Correct Option: C

Let the number be 10x + y.
Dividend = Divisor × quotient + remainder
∴  10x + y = 6(x + y) + 3
⇒  10x + y = 6x + 6y + 3
⇒  10x – 6x + y – 6y = 3
⇒  4x – 5y = 3     ....(i)
Again, 10y + x = 4 (x + y) + 9
⇒  10y + x = 4x + 4y + 9
⇒  6y – 3x = 9
⇒  2y – x = 3     ....(ii)
∴  By equation (i) + 4 × (ii),


4x – 5y = 3
8y – 4x = 12
____________
3y = 15
⇒y = 5

From equation (ii),
2 × 5 – x = 3 ⇒  x = 10 – 3 = 7
∴  Sum of digits = x + y = 7 + 5 =12



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