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Find the number of prime factors in the product of 2512 × 107 × 147.
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- 50
- 52
- 51
- 54
Correct Option: B
We break each base number into prime factors.
Now, 2512
= (5 × 5)12 = 512 × 512
107 = (2 × 5)7 = 27 × 57
and , 147 = (2 × 7)7 = 27 × 77
∴ 2512 × 107 × 147 = 512 × 512 × 27 × 57 × 27 × 77
= 512 + 12 + 7 × 27 + 7 × 77 = 531 × 214 × 77
∴ Number of prime factors = 31 + 14 + 7 = 52