A tap takes 36 hours extra to fill a tank due to a leakage

A tap takes 36 hours extra to fill a tank due to a leakage equivalent to half of its inflow. The inflow can fill the tank in how many hours?

Let the inflow fill the tank in t hours.
According to question ,

∴	1	-	1	=	1
	t		2t		36

[leakage being half of inflow]

⇒	2 - 1	=	1
	2t		36

⇒ 2t = 36

⇒ t =	36	= 18 hours
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