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Pipe A can fill a tank in 4 hours and pipe B can fill it in 6 hours. If they are opened on alternate hours and if pipe A is opened first, in how many hours, the tank shall be full ?
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4 1 2
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3 1 2
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3 1 4
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4 2 3
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Correct Option: D
On the basis of given details in question ,
Part of tank filled in first two hours = | + | = | = | ||||
4 | 6 | 12 | 12 |
Part of tank filled in first 4 hours = | = | ||
12 | 6 |
Remaining part = 1 – | = | ||
6 | 6 |
This remaining part willl be filled by pipe A.
Time taken by pipe A = | × 4 = | hours | ||
6 | 3 |
&there; Total time = 4 + | = 4 | hours | ||
3 | 3 |