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A circular wire of diameter 42 cm is folded in the shape of a rectangle whose sides are in the ratio 6 : 5 . Find the area enclosed
by the rectangle. (Take p = 22/7 )
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- 540 cm²
- 1080 cm²
- 2160 cm²
- 4320 cm²
- 540 cm²
Correct Option: B
Using Rule 9 and 14,
| Radius of circular wire = | = 21cm | |
| 2 |
Circumference of wire = 2πr
| = 2 × | × 21 = 132cm | |
| 7 |
Let the length and breadth of rectangle be 6 x and 5 x cm respectively.
∴ Perimeter of rectangle = 2 (6x + 5 x) = 22 x
According to the question, 22x = 132
| ⇒ x = | = 6 | |
| 22 |
∴ Length of rectangle = 6x = 6 × 6 = 36 cm
Breadth of rectangle = 5x = 5 × 6 = 30 cm
∴ Area = 36 × 30 = 1080 cm²
