ABC is a triangle with base AB. D is a point on AB such

Home » Aptitude » Mensuration » Question

ABC is a triangle with base AB. D is a point on AB such that AB = 5 and DB = 3. What is the ratio of the area of ∆ ADC to the area of ∆ ABC ?

Using Rule 1,

Given : AB = 5 DB = 3
∴ AD = 5 – 3 = 2
In the figure we can see that both ∆ ADC and ∆ ABC have the same height, h.

Area of a triangle =	1	× base × height
	2

When height is constant,
We know, Area of triangle a base,

∴	Area of ∆ ADC	=	AD	=	2
	Area of ∆ ABC		AB		5