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  1. The area of the triangle formed by the straight line 3x + 2y = 6 and the co-ordinate axes is
    1. 3 square units
    2. 6 square units
    3. 4 square units
    4. 8 square units
Correct Option: A

Putting y = 0 in the equation
3x + 2y = 6,
3x + 0 = 6 ⇒ x = 2

∴ Point of intersection on x-axis = (2, 0)
Putting x = 0, in the equation 3x + 2y = 6,
gives 0 + 2y = 6 ⇒ y = 3
∴ Point of intersection on y-axis = (0, 3)
So, OA = 2, OB = 3

∴ ∆ OAB =
1
× OA × OB
2

=
1
× 2 × 3 = 3 sq.units
2



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