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The area of an isosceles triangle is 4 square unit. If the length of the third side is 2 unit, the length of each equal side is
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- 4 units
- 2√3 units
- √17 units
- 3√2 units
- 4 units
Correct Option: C
Using Rule 1,
Let, AB = AC = x units
BD = DC = 1 unit [∵ BC = 2 units]
Now, AD = √AB² - BD²
= √x² - 1
∴ | × BC × AD = 4 | |
2 |
⇒ | × 2 × √x² - 1 = 4 | |
2 |
⇒ √x² - 1 = 4
⇒ x² – 1 = 16
⇒ x² = 17
⇒ x = √17units