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In •ABC, D and E are the points of sides AB and BC respectively such that DE || AC and AD : DB = 3 : 2. The ratio of area of trapezium ACED to that of ∆ BED is
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- 4 : 15
- 15 : 4
- 4 : 21
- 21 : 4
- 4 : 15
Correct Option: D
DE ∥ AC ∴ ∆ DBE ≅ ∆ ABC
= | = | |||
DB | EB | 2 |
+ 1 = | + 1 | ||
DB | 2 |
⇒ | = | ||
DB | 2 |
∴ | = | = | |||
∆ DBE | BD² | 4 |
⇒ | - 1 = | - 1 | ||
∆ DBE | 4 |
⇒ | = | ||
∆ DBE | 4 |
⇒ | = | or 21 : 4 | ||
∆ DBE | 4 |