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Three circles of radius 3.5 cm each are placed in such a way that each touches the other two. The area of the portion enclosed by the circles is
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- 1.975 cm²
- 1.967 cm²
- 19.67 cm²
- 21.21 cm²
- 1.975 cm²
Correct Option: B
Using Rule 6 and 17,
Radius of each circle = 3.5 cm From the figure.
∆ ABC will be an equilateral triangle of side 7 cm each.
Now, the required area = Area of DABC – 3× (Area of a sector of angle 60° in a circle of radius 3.5 cm)
| = | × (7)² - 3 |  | × | × (3.5)² |  | cm² | |||
| 4 | 360 | 7 |
| = | | - 19.25 | | cm² | |
| 4 |
= [21.217 – 19.25] cm²
= 1.967 cm²
