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Three coins of the same size (radius 1 cm) are placed on a table such that each of them touches the other two. The area enclosed by the coins is
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π - √3 
cm² 2 -
√3 - π cm² 2 -
2√3 - π cm² 2 -
3√3 - π cm² 2
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Correct Option: B
Using Rule 6 AND 17,
Obviously, the triangle ABC will be equilateral.
AB = BC = CA = 2 cm.
Area of ∆ ABC
| = | × 2 × 2 | |
| 4 |
= √3 cm²
Then, area ‘A’ of the three sectors each of angle 60° in a circle of radius 1 cm.
| A = 3 × | × π × 1 = | ||
| 360 | 2 |
∴ Area of the shaded portion
| = | | √3 - | | cm². | |
| 2 |
