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The area of circle whose radius is 6 cm is trisected by two concentric circles. The radius of the smallest circle is
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- 2√3 cm
- 2√6 cm
- 2 cm
- 3 cm
- 2√3 cm
Correct Option: A
Using Rule 14,
Area of original circle = π × (6)2 = 36π cm²
After trisection, the area of the smallest circle
| = | × 36π = 12π | |
| 3 |
= π × (2√3)²
∴ Required radius = 2√3cm
