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The circumference of a circle is 11 cm and the angle of a sector of the circle is 60°. The area of
the sector is (use π = 22/7)
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1 29 cm² 48 -
2 29 cm² 48 -
1 27 cm² 48 -
2 29 cm² 48
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Correct Option: A
Using Rule 17,
Let the radius of the circle be r cm.
According to the question,
| 2πr = 11 ⇒ 2 × | r = 11 | |
| 7 |
| ⇒ r = | = | cm. | ||
| 2 × 22 | 4 |
| ∴ Area of the sector AOB = | × πr² | |
| 360° |
| = | × | × | × | sq. cm | ||||
| 360° | 7 | 4 | 4 |
| = | = 1 | sq.cm. | ||
| 48 | 48 |
