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A circle is inscribed in an equilateral triangle of side 8 cm. The area of the portion between the triangle and the circle is
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- 11 cm²
- 10.95 cm²
- 10 cm²
- 10.50 cm²
- 11 cm²
Correct Option: B
Using Rule 6 and 14,
Radius of in-circle = BD cot 60°
| = | cm | |
| √3 |
| Area of the circle = π × | × | ||
| √3 | √3 |
| = | π cm² = 16.76 cm² | |
| 3 |
| Area of the triangle = | × 8 × 8 | |
| 4 |
= 16√3 cm²
∴ Required area = 16√3 – 16.76
= (27.71 – 16.76) = 10.95 cm²
