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The sides of a triangle are 6 cm, 8 cm and 10 cm. The area of the greatest square that can be inscribed in it, is
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- 18 cm²
- 15 cm²
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2304 cm² 49 -
576 cm² 50
- 18 cm²
Correct Option: D
Using Rule 1,
Here, 6² + 8² = 10²
Hence, ∆ABC is right angled BD is perpendicular to AC
| ∴ | × AB × BC = | × AC × BD | ||
| 2 | 2 |
| ⇒ | × 6 × 8 = | × 10 × BD | ||
| 2 | 2 |
| ⇒ BD = | = | ||
| 10 | 5 |
∴ BD = diagonal of square
| ∴ Area of square = | |
| 2 × 5 × 5 |
| = | cm² | |
| 50 |