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A circle is inscribed in an equilateral triangle and a square is inscribed in that circle. The ratio of the areas of the triangle and the square is
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- √3 : 4
- √3 : 8
- 3√3 : 2
- 3√3 : 1
Correct Option: C
Let AB = BC = CA = x units, then
AD = √ | x² - | = | ||
4 | 2 |
OD = | AD = | = radius of circle | ||
3 | 2√3 |
⇒ Diagonal of square = 2 × | = | ||
2√3 | √3 |
∴ Triangle : Square
= | x² : | ||
4 | 2 × 3 |
= | : | = 3√3 : 2 | ||
2 | 3 |