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If a wire is bent into the shape of a square, the area of the square is 81 sq. cm. When the wire is bent into a semicircular shape, the area of the semicircle (taking π = 22/7 ) is :
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- 154 cm²
- 77 cm²
- 44 cm²
- 22 cm²
- 154 cm²
Correct Option: B
Using Rule 10,
The length of wire
= perimeter of the square
= 4 × √Area of square
= 4 × √81
= 4 × 9 = 36 cm
Now, perimeter of semicircular shape = 36 cm
⇒ (π × r + 2r) = 36 cm.
⇒ r | + 2 | ² | = 36 cm | |||
7 |
⇒ r × | = 36 | |
7 |
⇒ r × | = 7 cm | |
7 |
∴ Required area = | = | = 77 cm² | ||
2 | 7 × 2 |