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A straight line parallel to the base BC of the triangle ABC intersects AB and AC at the points D and E respectively. If the area of the ∆ABE be 36 sq.cm, then the area of the ∆ACD is
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- 18 sq.cm
- 36 sq.cm
- 18 cm
- 36 cm
- 18 sq.cm
Correct Option: B
∆DBC and ∆EBC lie on the same base and between same parallel lines.
∴ ∆DBC = ∆BEC
⇒ ∆ABC ~ ∆DBC
⇒ ∆ABC ~ ∆BEC
⇒ ∆ADE = ∆ABE = 36 sq.cm
