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ABC is a right angled triangle, B being the right angle. Mid-points of BC and AC are respectively B' and A'. The ratio of the area of the quadrilateral AA' B'B to the area of the triangle ABC is
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- 1 : 2
- 2 : 3
- 3 : 4
- None of the above
- 1 : 2
Correct Option: C
A'B'C ~ ∆ABC
∠C = ∆C,
= | and | = | ||||
CA | 2 | CB | 2 |
and
∴ | = | = | |||
∆A'B'C | x² | 1 |
[ ∵ BC = 2B'C and AC = 2A'C]
⇒ | = | ||
∆ABC | 4 |
⇒ 1 - | = 1 - | ||
∆ABC | 4 |
⇒ | = | = 3 : 4 | ||
∆ABC | 4 |