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a and b are two sides adjacent to the right angle of a right-angled triangle and p is the perpendicular drawn to the hypotenuse from the opposite vertex. Then p2 is equal to
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- a² + b²
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1 + 1 a² b² -
a²b² a² + b² - a² – b²
- a² + b²
Correct Option: C
Using Rule 1, 
BD ⊥ AC
AB ⊥ BC
Hypotenuse of ∆ABC = √AB² + BC²
= √a² + b²
| Area of ∆ABC = | × AB × BC | |
| 2 |
| = | × AC × BD | |
| 2 |
⇒AB × BC = AC × BD
⇒ ab = √a² + b² × p
On squaring both sides,
a²b² = (a² + b²) p²
| ∴ p² = | ||
| a² + b² |
