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					 In ∆ABC, D and E are two points on the sides AB and AC respectively so that DE||BC andAD = 2 BD 3 Then the area of trapezium DECB is equal to the area of ∆ABC 
 
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                        -  5/9 
 
-  21/25
 
-  1 4 5 
-  5 1 4 
 
-  5/9 
Correct Option: B

DE || BC 
∴ ∠ADE = ∠ABC
∠AED = ∠ACB 
∴ ∆ADE ~ ∆ABC
| ∴ | = | ||
| BD | 3 | 
| ⇒ | = | ||
| AD | 2 | 
| = | + 1 = | + 1 | ||
| AD | 2 | 
| ⇒ | |
| AD | 
| ⇒ | ⇒ | = | |||
| 2 | AD | 2 | 
| ∴ | = | = |  |  | ² | = | ||||
| Area of ∆ABC | AB² | 5 | 25 | 
| ⇒ 1 - | = 1 - | ||
| Area of ∆ABC | 25 | 
| ⇒ | = | ||
| Area of ∆ABC | 25 | 
| ∴ | = | ||
| Area of ∆ABC | 25 |