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If the length of each of two equal sides of an isosceles triangle is 10 cm. and the adjacent angle is 45°, then the area of the triangleis
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- 20√2 square cm.
- 12√2 square cm.
- 25√2 square cm.
- 15√2 square cm.
- 20√2 square cm.
Correct Option: C
| AD = AB sin 45° = 10 × | = 5√2 cm. | |
| √2 |
∴ Area of ∆ABC
| = | × BC × AD | |
| 2 |
| = | × 10 × 5√2 | |
| 2 |
= 25√2 square cm.
