ABCD is a square inscribed in a circle of radius r. Then

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ABCD is a square inscribed in a circle of radius r. Then the total area (in square units) of the portions of the circle lying outside the square is

Using Rule 10 and 14,

Radius of circle = r units
Area of circle = πr² sq. units
In square ABCD Diagonal = BD = 2r units

∴ Area of square =	1	× (2r)² = 2r²
	2

∴ Required difference = πr² – 2r² = r² (π – 2) sq. units