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The diagonal of a quadrilateral shaped field is 24m and the perpendiculars dropped on it from the remaining opposite vertices are 8m and 13m. The area of the field is
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- 252 m²
- 156 m²
- 96 m²
- 1152 m²
- 252 m²
Correct Option: A
Using Rule 1, 
AC = 24 metre
BE = 8 metre
DF = 13 metre
∴ Area of quadrilateral ABCD
= Area of ∆ABC + Area of ∆ACD
| = | × AC × BE + | × AC × DF | ||
| 2 | 2 |
| = | (24 × 8 + 24 × 13 | |
| 2 |
| = | × 24 (18 + 13) | |
| 2 |
| = | × 24 × 21 = 252 sq metre | |
| 2 |
