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In trapezium ABCD, AB ||CD and AB = 2CD. Its diagonals intersect at O. If the area of ∆AOB = 84 cm², then the area of ∆COD is equal to
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- 72 cm²
- 21 cm²
- 42 cm²
- 26 cm²
- 72 cm²
Correct Option: B
DC || AB
∠DCA = ∠CAB
∠CDB = ∠DBA
∴ ∆COD ~ ∆AOB
| ∴ | |
| Area of ∆AOB |
| = | = | = | |||
| AB² | 4CD² | 4 |
∴ Area of ∆COD
| = | × 84 | |
| 4 |
= 21 sq. cm.
