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A square and a regular hexagon are drawn such that all the vertices of the square and the hexagon are on a circle of radius r cm. The ratio of area of the square and the hexagon is
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- 3 : 4
- 4 : 3√3
- √2 : √3
- 1 : √2
- 3 : 4
Correct Option: B
Diagonal of square = 2r cm.
| ∴ Area of square = | × (2r)² = 2r² sq.cm. | |
| 2 |
| Area of ∆OAB = | r² sq.cm. | |
| 4 |
| ∴ Area of hexagon = | r² | |
| 4 |
| = | r² sq.cm. | |
| 2 |
| ∴ Required ratio = 2r² : | r² | |
| 2 |
= 4 : 3√3
