∆ABC is similar to ∆DEF. If the area of ∆ABC

Home » Aptitude » Mensuration » Question

∆ABC is similar to ∆DEF. If the area of ∆ABC is 9 sq.cm. and the area of ∆DEF is 16 sq.cm. and BC = 2.1 cm, then the length of EF will be

∆ABC ~ ∆DEF

∴	Area of ∆ABC	=	BC²
	Area of ∆DEF		EF²

⇒	9	=	(2.1)²
	16		(EF)²

⇒	3	=	2.1
	4		EF

⇒ EF =	4 × 2.1	2.8 cm
	3