Home » Aptitude » Mensuration » Question
  1. If two medians BE and CF of a triangle ABC, intersect each other at G and if BG = CG, angle BGC = 120°, BC = 10 cm, then area of the triangle ABC is :
    1. 50√3 cm²
    2. 60 cm²
    3. 25 cm²
    4. 25√3 cm²
Correct Option: D


BG = GC, ∠BGC = 120°
∴ ∠GBC = ∠GCB = 30°
∴ ∆ABC is an equilateral triangle.

∴ Area of ∆ABC =
3
× side²
4

=
3
× 10 × 10
4

= 25√3 Sq. cm.



Your comments will be displayed only after manual approval.