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If two medians BE and CF of a triangle ABC, intersect each other at G and if BG = CG, angle BGC = 120°, BC = 10 cm, then area of the triangle ABC is :
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- 50√3 cm²
- 60 cm²
- 25 cm²
- 25√3 cm²
Correct Option: D
BG = GC, ∠BGC = 120°
∴ ∠GBC = ∠GCB = 30°
∴ ∆ABC is an equilateral triangle.
| ∴ Area of ∆ABC = | × side² | |
| 4 |
| = | × 10 × 10 | |
| 4 |
= 25√3 Sq. cm.
