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In a trapezium ABCD, AB || CD, AB < CD, CD = 6 cm and distance between the parallel sides is 4 cm. If the area of ABCD is 16 cm², then AB is
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- 1 cm
- 2 cm
- 3 cm
- 8 cm
- 1 cm
Correct Option: B
| Area of the trapezium ABCD = | (AB + CD) × AE | |
| 2 |
| ⇒ 16 = | (AB + 6) × 4 | |
| 2 |
⇒ 16 = 2(AB + 6)
⇒ AB + 6
| = | = 8 ⇒ AB = 8 – 6 = 2 cm. | |
| 2 |
