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In an equilateral triangle of side 24 cm., a circle is inscribed touching its sides. The area of the remaining portion of the triangle is approximately equal to assuming π = 22/7 & √3 = 1.732
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- 36.6 cm²
- 54.2 cm²
- 72.8 cm²
- 98.5 cm²
- 36.6 cm²
Correct Option: D
| Radius of circle = | ||
| 2√3 |
| = | = 4√3 cm | |
| 2√3 |
∴ Area of circle = π (4√3)²
= 48π sq. cm.
| = |  | 48 × |  | sq. cm | |
| 7 |
= 150.86 sq. cm.
| Area of ∆ABC = | | × 24 × 24 | | sq. cm | |
| 4 |
= 144 × 1.732
= 249.408 sq. cm.
∴ Area of the shaded region
= (249.408 – 150.86) sq. cm.
= 98.548 sq. cm.
