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The area of a triangle ABC is 10.8 cm². If CP = PB and 2AQ = QB, then the area of the triangle APQ is
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- 3.6 cm²
- 0.9 cm²
- 2.7 cm²
- 1.8 cm²
- 3.6 cm²
Correct Option: D
AP is the median at BC.
∴ Area of ∆ABP = Area of ∆APC
Again, 2AQ = QB
| ∴ Area of ∆APQ = | Area of ∆ABP | |
| 3 |
| ∴ Area of ∆APQ = | Area of ∆ABC | |
| 6 |
| = |  | × 10.8 |  | sq. cm | |
| 6 |
= 1.8 sq.cm.
