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  1. D, E and F are the mid points of the sides BC, CA and AB respectively of a ∆ABC. Then the ratio of the areas of ∆DEF and ∆ABC is
    1. 1/2
    2. 1/4
    3. 1/8
    4. 1/16
Correct Option: B


EF || CB and FE = 1/2 BC
∆DFE ~ ∆ABC

Area of ∆DEF
=
EF²
Area of ∆ABCBC²

=
EF²
=
1
4EF²4



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