A circular wire of radius 42 cm is bent in the form of a

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A circular wire of radius 42 cm is bent in the form of a rectangle whose sides are in the ratio of 6 : 5. The smaller side of the rectangle is (Take π = 22/7)

Using Rule 7, Circumference of the circular wire = 2&pir

= 2 ×	22	× 42 = 264 cm
	7

⇒ Perimeter of rectangle = 264 cm
Let the sides of rectangle be 6x and 5x cm.
∴ 2 (6x + 5x) = 264
⇒ 2 × 11 x = 264

⇒ x =	264	= 12
	22

∴ The smaller side = 5x = 5 × 12 = 60 cm.