If the perimeter of a semicircular field is 144m, then the

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If the perimeter of a semicircular field is 144m, then the diameter of the field is (take π = 22/7)

1. 55m
2. 30m
3. 28m
4. 56m

Correct Option: D

Using Rule 14,
If the radius be r metre, then πr + 2r = 144
⇒ r (π + 2) = 144

⇒ r =	144	=	144		=	144 × 7	= 28
	π + 2		22	+ 2		36
			7

∴ Diameter = 2r = 2 × 28 = 56 metre