-
A circular road runs around a circular ground. If the difference between the circumference of the outer circle and the inner circle is 66 metres, the width of the road is:(Take π = 22/7)
-
- 10.5 metres
- 7 metres
- 5.25 metres
- 21 metres
- 10.5 metres
Correct Option: A
Breadth of road = r2 – r1
∴ 2πr2 - 2πr1 = 66
→ 2π(r2 - r1) = 66
| r2 - r1 = | = | |||
| 2π | 2 × 22 |
= 10.5 metres
