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A path of uniform width surrounds a circular park. The difference of internal and external circumference of this circular path is 132 metres. Its width is : (Take π = 22/7 )
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- 22m
- 20 m
- 21m
- 24m
- 22m
Correct Option: C
Let the internal radius of the park be r and the external radius (with the path) be R.
The difference between the internal and external circumferences is 132 m.
i.e. 2πR – 2πr = 132
⇒ 2π (R – r) = 132
| ⇒ R – r = | = | = 21 | ||
| 2π | 2 × 22 |
Hence, the width of path = 21 metres
