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A wire when bent in the form of a square encloses an area of 484 sq. cm. What will be the enclosed area when the same wire is bent into the form of a circle? (Take π = 22/7 )
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- 462 sq.cm
- 539 sq.cm
- 616 sq.cm
- 693 sq.cm
- 462 sq.cm
Correct Option: C
Using Rule 10 and 14,
Area of the square = (side)²
484 sq.cm. = (side)²
Side =√484 = 22 cm
∴ Perimeter of the square = 4 × side = 4 × 22 = 88 cm
According to the question, the circle is made by same wire.
Therefore,
Perimeter of the square = circumference of the circle 88 cm = 2πr
| 88cm = 2 × | × r | |
| 7 |
| ⇒ r = | = 14 cm | |
| 2 × 22 |
∴ Area of circle = πr²
| = | × (14)² = | × 14 × 14 | ||
| 7 | 7 |
= 616 sq.cm.
