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The height of the cone is 30 cm. A small cone is cut off at the top by a plane parallel to its base. If its volume is 1/27 of the volume of the cone, at what height, above the base, is the section made?
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- 6 cm
- 8 cm
- 10 cm
- 20 cm
- 6 cm
Correct Option: D
Let H and R be the height and radius of bigger cone respectively and h and r that of smaller cone.
From triangles AOB and AMN. ∠A is common and MN || OB.
∴ Triangles AOB and AMN are similar,
∴ | = | ||
AM | MN |
⇒ | = | .........(i) | ||
h | r |
∴ Volume = | πr² × h | |
3 |
Volume of bigger cone = | πR²H | |
3 |
According to the question,
πr²h = | πR²H | × | |||||
3 | 3 | 27 |
⇒ r²h = | ⇒ 27r²h = R²H | |
27 |
⇒ | = | ||
H | r² |
⇒ | = | ² | From(i) | ||||
H | h |
⇒ | = | ||
H | r² |
⇒ 27h³ = 900H = 900 × 30
h³ = | = 1000 | |
27 |
⇒ h = 3√1000 = 10 cm
∴ Required height = 30 – 10 = 20 cm