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Two solid right cones of equal height and of radii r1 and r2 are melted and made to form a solid sphere of radius R. Then the height of the cone is
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4R² r1² + r2² -
4R r1 + r2 -
4R³ r1² + r2²
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R² r1² + r2²
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Correct Option: C
Let the height be h units.
| ∴ | πh(r1² + r2²) = | π R³ | ||
| 3 | 3 |
⇒ h(r1² + r2²) = 4R³
| ∴ V = | πr²h | |
| 3 |
