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If the base of a right pyramid is triangle of sides 5 cm, 12 cm, 13 cm and its volume is 330 cm³, then its height (in cm) will be
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- 33
- 32
- 11
- 22
- 33
Correct Option: A
| Area of base = Area of right angled triangle = | × 5 × 12 = 30 sq.cm. | |
| 2 |
[∵ 5² + 12² = 13²]
| ∴ Volume = | × Area of base × height | |
| 3 |
| ⇒ 330 = | × 30 × h | |
| 3 |
| ⇒ 330 = | × 33 cm./td> | |
| 10 |
