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The diameter of the iron ball used for the shot-put game is 14 cm. It is melted and then a solid cylinder of height
2 1 cm 3
is made. What will be the diameter of the base of the cylinder ?
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- 14 cm
- 28 cm
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14 cm 3 -
28 cm 3
- 14 cm
Correct Option: B
Radius of the iron ball = 14/2 = 7 cm
| Volume of the ball = | π × (7)³ = 3³ | |
| 3 |
Let the radius of cylinder be r cm.
| ∴ Volume of cylinder = πr² × | cm³ | |
| 3 |
Clearly,
| π r² × | = | π × (7)³ | ||
| 3 | 3 |
| ⇒ r² = | ||
| 7 × 3 |
⇒ r = √4 × 7 × 7 = 14 cm
∴ Diameter = 2 × 14 = 28 cm
