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The radius of cross-section of a solid cylindrical rod of iron is 50 cm. The cylinder is melted down and formed into 6 solid spherical balls of the same radius as that of the cylinder. The length of the rod (in metres) is
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- 0.8
- 2
- 3
- 4
- 0.8
Correct Option: D
Let Length of rod = x cm
∴ Volume of cylinder = Volume of 6 spheres
| ⇒ πr²h = 6 × | πr³ | |
| 3 |
| ⇒ πr²h = 6 × | × r = 8 × 50 = 400 cm = 4 metre | |
| 3 |
