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The radius of the base and the height of a right circular cone are doubled. The volume of the cone will be
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- 8 times of the previous volume
- three times of the previous volume
- 32 times of the previous volume
- 6 times of the previous volume
- 8 times of the previous volume
Correct Option: A
| Volume of a cone = | πr²h | |
| 3 |
Again, r1 = 2r, h1 = 2h
| ∴ Volume of the second cone = | πr1²h1 | |
| 3 |
| ∴ Volume of the second cone = | π(2r)² × (2h) | |
| 3 |
| ∴ Volume of the second cone = | πr²h × 8 | |
| 3 |
= Eight times of the previous volume
