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A cylindrical container of 32 cm height and 18 cm radius is filled with sand. Now all this sand is used to form a conical heap of sand. If the height of the conical heap is 24 cm, what is the radius of its base ?
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- 12 cm
- 24 cm
- 36 cm
- 48 cm
- 12 cm
Correct Option: C
Volume of sand = Volume of cylindrical vessel = πr²h
= π × (18)² × 32 cu.cm.
Volume of conical heap = π × 18 × 18 × 32
| ⇒ | πR²H = × π × 18 × 18 × 32 | |
| 3 |
| ⇒ | × R² × 24 = 18 × 18 × 32 | |
| 3 |
| ⇒ R² = | = 1296 | |
| 24 |
⇒ R = √1296 = 36 cm.
