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The radius of cross section of a solid right circular cylindrical rod is 3.2 dm. The rod is melted and 44 equal solid cubes of side 8 cm are formed. The length of the rod is : (Take π = 22/7)
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- 56 cm.
- 7 cm.
- 5.6 cm.
- 0.7 cm.
- 56 cm.
Correct Option: B
Volume of cylindrical rod = 44 × volume of solid cube
⇒ πr²h = 44 × (edge)³
| ⇒ | × 32 × 32 × h | |
| 7 |
= 44 × 8 × 8 × 8
| ⇒ h = | = 7 cm. | |
| 22 × 32 × 32 |
