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					 If the sum of three dimensions and the total surface area of a rectangular box are 12 cm and 94 cm² respectively, then the maximum length of a stick that can be placed inside the box is
 
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                        -  5√2 cm 
 
-  5 cm 
 
-  6 cm 
 
- 2√5cm
 
-  5√2 cm 
Correct Option: A
Let the length, breadth and height of the box be x, y and z cm respectively. 
∴ x + y + z = 12 ...(i) 
and 2 (xy + yz + zx) = 94   ...(ii) 
∴ (x + y + z)² = x² + y² + z² + 2xy + 2yz + 2zx 
⇒ 144 = x² + y² + z² + 94 
→ x² + y² + z² = 144 – 94 = 50 
∴ Maximum length of stick = √x² + y² + z²
= √50 = 5√2cm
 
	