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The length of the largest possible rod that can be placed in a cubical room is 35 3 m. The surface area of the largest possible sphere that fit within the cubical room (assuming π = 22/7 ) (in squarem)is
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- 3,500
- 3,850
- 2,450
- 4,250
- 3,500
Correct Option: B
Diagonal of cubical room = 35√3metre
∴ 3 × edge = 35√3
⇒ Edge = 35 metre
→ Diameter of sphere = 35 metre
⇒ Surface area of the sphere = 4πr²
| = 4 × | × | = 3850 sq.metre | ||
| 7 | 4 |
