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If S1 and S2 be the surface area of a sphere and the curved surface area of the circumscribed cylinder respectively, then S1 is equal to
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3 S2 4 -
1 S2 2 -
3 S2 3 - S2
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Correct Option: B
S1 = surface area of sphere = 4πr²
S2 = curved surface of the circumscribed cylinder
= 2πRH = 2π (2r) (2r) = 8πr²
⇒ | πR³= | πR³H | ||
3 | 3 |
∴ | = | = | |||
S2 | 8πr² | 2 |
⇒ S1 = | S2 | |
2 |